Day 128 – March 16

Algebra: Chapter 11, Lesson 5, page 498.

Dividing and Simplifying

The `sqrt` of quotients is pretty simple. You can combine or break apart quotient `sqrt`s to your liking.

Try to find perfect squares and make sure that all the factors are simplified.

Division Property for Radicals:

`sqrt(a/b) = sqrt(a)/sqrt(b)` Remember too, that you can go back and forth without any problem.

Remember too, to “rationalize the denominator”. Make sure that NO radical appears in the denominator. If you have one, multiply the numerator and denominator by 1 (the `sqrt` of the denominator) to make it disappear. The `sqrt(a) * sqrt(a) = sqrt(a^2) = a`!

An expression containing radicals is simplified when the following conditions are met:

  • The radicand contains NO perfect square factors
  • A fraction in simplest form does not have a radical in the denominator
  • A simplified radical does not contain a fractional radicand.

For example:

`sqrt(2)/sqrt(3) = sqrt(2)/sqrt(3) * sqrt(3)/sqrt(3)`

`= [sqrt(2) * sqrt(3)] / [sqrt(3) * sqrt(3)]`

`= sqrt(6)/3 = [1/3] * sqrt(6)`

See this link from purplemath.com.

Here again is a great link from Purplemath.

Two of tonight’s homework problems solved by MrE are here! Just click it.

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Algebra 1a: Chapter 9, Lesson 2, page 405.

Compound Sentences

Conjunctions and Disjunctions are like Intersections and Unions (respectively) from lesson 9-1.

A disjunction of 2 statements is formed by connecting them with the word “or”. A disjunction is true when one OR both statements are true.

A conjunction of 2 statements is formed by connecting them with the word “and”. A conjunction is true when both statements are true.

Two of tonight’s homework problems solved by MrE are here! Just click it!

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