Algebra: Chapter 10, Lesson 2, page 436.
Multiplying Rational Expressions
To multiply rational numbers, we multiply the numerators and multiply the denominators. We multiply rational expressions in the same way.
For example, we have the following examples:
`–2/(2y+6)⋅3/(y–5)`
First multiply the numerators and the denominators so that is looks like
`(-2⋅3)/((2y+6)(y-5))` which becomes `(-2⋅3)/((2)(y+3)(y-5))` and finally is `=-3/((y+3)(y-5))`!
Another example is:
`4/(5x^2)⋅(x-2)/(2x^3)`
Multiplying numerators and denominators again, we have it becoming
`(4(x-2))/(10x^5)` which turns into `(2(x-2))/(5x^5)`
Here is a link from purplemath.com as well with more information and examples.
Two of tonight’s homework problems solved by MrE are here! Just click it!
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Algebra 1a: Chapter 7 Review for Algebra Benchmark (#5)
Algebra Benchmark #5 Practice and Review were started in class. The end of the Chapter Review is a good overview and practice of the entire chapter.
Remember, to solve problems using the slope-intercept formula, `y = mx + b`, you need to have (or solve first for) the slope, then using one of the ordered pairs given `(x, y)` solve for the y-intercept, b.
Given the slope `m`, and the y-intercept `b`, we can develop the equation by plugging in the values for the slope and the y-intercept.
An equation perpendicular to the given one will have to have its slope be the negative reciprocal for the product to be -1. In other words, `m_1 * m_2 = -1`
A new equation that has to be parallel to the given one, must have its slope be exactly the same, `m_1 = m_2`!