Day 106 – February 11

Algebra: Chapter 6, Lesson 3, page 270

Trinomial Squares

We are going backward again, using the properties:

• ${\displaystyle (a+b)(a+b)=a^2+2ab+b^2={(a+b)}^2}$
• ${\displaystyle (a–b)(a–b)=a^2–2ab+b^2={(a–b)}^2}$

For a trinomial square to factor, we must make sure that:

• 2 of the terms must be squares, ${\displaystyle a^2}$ and ${\displaystyle b^2}$
• There must be NO MINUS sign before the ${\displaystyle a^2}$ and ${\displaystyle b^2}$
• If we multiply ${\displaystyle a}$ and ${\displaystyle b}$ and double the result, we get the 3rd term, ${\displaystyle 2ab}$ or its additive inverse ${\displaystyle -2ab}$.

Sometimes, we can also factor out a coefficient in front of the ${\displaystyle a^2}$, like ${\displaystyle 2a^{}}$. We MIGHT be able to factor out the ${\displaystyle 2}$ before we start the trinomial determination.

Here is a purplemath link that describes trinomial squares, scroll down about 1/2 way to get to the information.

Two of tonight’s homework problems solved by MrE are here! Just click it!

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Algebra 1a: Chapter 8, Lesson 2 and 3 Review, page 362 and 367 – DAY #3

Substitution Method and Addition and Subtraction for 2 linear equations.

See Monday and Tuesday’s lesson. We may sometimes have to scale (multiply) ONE OR BOTH of the equations to make one of the variables disappear. Here is a link that can help!

Two of tonight’s homework problems solved by MrE are here! Just click it!

The worksheets page 8.2 and 8.3 will give us a little more practice before continuing with the rest of Chapter 8!