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Category Archives: Algebra 1a
Day 151 – April 28
Algebra: Chapter 13, Lesson 6, page 598. Solving Radical Equations We can solve radical equations by first using the principle of squaring to find the quadratic equation. Remember, squaring a square root results in the stuff under the radical being … Continue reading
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Day 150 – April 27
Algebra: Chapter 13, Lesson 5, page 595. Solving Rational Equations Remember, we solve rational equations by multiplying both sides by the LCM of all the denominators. This can result in a quadratic equation. Sometimes, there can be extraneous solutions, so … Continue reading
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Day 149 – April 26
Algebra: Chapter 13, Lesson 4, page 589. The Quadratic Formula, finally! Given that `ax^2 + bx + c = 0`, then the quadratic formula `x = (−b±sqrt(b^2−4ac))/(2a)` gives the solutions of the quadratic equation. This requires that the quadratic equation … Continue reading
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Day 148 – April 23
Algebra: Chapter 13, Lesson 3, page 586 AND Chapter 13, Lesson 2, page 580 (because of yesterday’s snow day and the upcoming CST/STAR testing (ugh …). Solving quadratics by completing the squares We can use the technique of completing the … Continue reading
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Day 146 – April 21
Algebra: Chapter 13, Lesson 1, page 576. Introduction to Quadratic Equations An equation that can be written in the form of `ax^2 + bx + c = 0` is a quadratic equation. This is the “standard form”. The solutions of … Continue reading
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Day 145 – April 20
Algebra: Chapter 12, Lesson 4, page 552. Quadratic Functions A quadratic function is defined by `f(x) = ax^2 + bx + c`. To make it easier, just replace the `f(x)` with `y` and treat as you have done in the … Continue reading
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Day 144 – April 19
Algebra: Chapter 11, Lesson 9, page 519. Equations with Radicals A radical equation contains a variable in the radicand. To solve radical equations, first convert them to equations without radicals. Just like taking the square root of 2 sides of … Continue reading
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Day 143 – April 16
Algebra: Chapter 11, Lesson 7 and Lesson 8, pages 509 and 514. Theorem of Pythagoras and its Uses `c^2 = a^2 + b^2`, where `a`, `b` and `c` are the sides of a RIGHT TRIANGLE. `a` and `b` are considered … Continue reading
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Day 142 – April 15
Algebra: Chapter 11, Lesson 7 and Lesson 8, pages 509 and 514. Theorem of Pythagoras and its Uses `c^2 = a^2 + b^2`, where `a`, `b` and `c` are the sides of a RIGHT TRIANGLE. `a` and `b` are considered … Continue reading
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